Home
Class 11
CHEMISTRY
Electrons are emitted with zero velocity...

Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength ` 6800` Å . Calculate threshold frequency `( v_0)` and work function `(W_0)` of the metal.

Text Solution

Verified by Experts

Threshold wavelength `(lambfa_(0))=6800 Å=6800xx10^(-10) m`
As `c=v lambda :. v_(0)=c/lambda_(0)=(3.0xx10^(8)" ms"^(-1))/(6800xx10^(-10) m)=4.41xx10^(14) s^(-1)`
Work function `(W_(0))=hv_(0)=(6.626xx10^(-34) J s)(4.41xx10^(14) s^(-1))=2.92xx10^(-19) J`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    PRADEEP|Exercise NCERT Exemplar Problems With Answers, Hints and Solution (I. Multiple Choice Questions)|16 Videos
  • STRUCTURE OF ATOM

    PRADEEP|Exercise NCERT Exemplar Problems With Answers, Hints and Solution (II. Multiple Choice Questions)|5 Videos
  • STRUCTURE OF ATOM

    PRADEEP|Exercise Conceptual Questions|44 Videos
  • STATES OF MATTER: SOLID MATTER

    PRADEEP|Exercise COMPETITION FOCUS (ASSERTION-REASON)|17 Videos
  • THERMODYNAMICS

    PRADEEP|Exercise MULTIPLE CHOICE QUESTION ( BASED ON PRACTICAL CHEMISTRY)|3 Videos

Similar Questions

Explore conceptually related problems

(a) Define Photoelectric effect ? Mention its one practical application in daily life. (b) Electrons are emitted with zero velocity from a mental surface when it is exposed to radiation of wavelength 6800 Å. Calculate thresholds freqency (V_o) and work function (W_o) of the mental.

A metal has a threshold wavelength fo 6000 Å . Calculate (i) threshold frequency (ii) work function. Will there be photoelectric emission or not ?

Knowledge Check

  • If a metal surface is exposed to electromagnetic radiation of frequency VgtV_0, then

    A
    photoelectric emission will not take place.
    B
    photoelectric emission will take place.
    C
    thermionic emission will take place.
    D
    photons will be emitted from it .
  • The kinetic energy of most energetic electrons emitted from a metallic surface is doubled when the wavelength lamda of the incident radiation is changed from 400 nm to 310 nm. The work function of the metal is

    A
    0.9 eV
    B
    1.7 eV
    C
    2.2 eV
    D
    3.1 eV
  • Similar Questions

    Explore conceptually related problems

    Electrons with maximum kinetic energy 3eV are ejected from a metla surface by ultraviolet radiation of wavelength 1500Å . Determine the work function of the metal, the threshold wavelength of metal and the stopping potential difference required to stoop the emission of electrons.

    When a certain metal was irradiated with light of frequency 1.6xx10^(16)Hz , the photoelectrons emitted had twice the kinetic energy as photoelectrons emitted when the same metal was irradiated with light of frequency 1.0xx10^(6)Hz . Calculate the threshold frequency (v_(0)) for the metal.

    Calculate the threshold freqency of the metalfrom the photoelectronsare emitted with zero velocity when exposed to radiation of wavelength 6800 Å Hint : KE = (1)/(2) mv^(2) hv= hv_(0) + KE, KE=0 v= (c ) /( lambda)

    Metal surface emits photoelectrons when light of wavelength 400 nm is incident on it. Calculate the work function of the metal if stopping potential is 0.5 V.

    Photo electrons are liberated by ultraviolet light of wavelength 3000 Å from a metalic surface for which the photoelectric threshold wavelength is 4000 Å . Calculate the de Broglie wavelength of electrons emitted with maximum kinetic energy.

    The kinetic energy of.most energetic electrons emitted from a metallic surface is doubled when the wavelength of the incident radiation is changed from 400 nm to 310 nm . The work function (in eV ) of the metal is