The velocity associated with a proton moving in a potential difference of `1000 V` is `4.37xx10^(5) m s^(-1)`. If the hockey ball of mass `0.1 kg` is moving with this velocity, calculate the wavelength associated with this velocity.

Explanation

`lamda = (h)/(mv) = (6.626 xx 10^(-34) kg m^(2) s^(-1))/((0.1lh) (4.37 xx 10^(5) ms^(-1))) = 1.516 xx 10^(-28) m`