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Calculate the energy in joule correspond...

Calculate the energy in joule corresponding to light of wavelength `45 nm` :
(Planck' constant `h = 6.63 xx 10^-34 Js` , speed of light `c = 3 xx 10^8 ms^-1`)

A

`6.67 xx 10^(15)`

B

`6.67 xx 10^(11)`

C

`4.42 xx 10^(-15)`

D

`4.42 xx 10^(-18)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = hv = (hc)/(lamda)`. Given `lamda = 45 nm = 45 xx 10^(-9) m`
`:. E = ((6.63 xx 10^(-34) Js) (3 xx 10^(8) ms^(-1)))/((45 xx 10^(-9) m))`
`= 4.42 xx 10^(-18) J`
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