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Calculate the energy in joule correspond...

Calculate the energy in joule corresponding to light of wavelength `45 nm` :
(Planck' constant `h = 6.63 xx 10^-34 Js` , speed of light `c = 3 xx 10^8 ms^-1`)

A

`6.67 xx 10^(15)`

B

`6.67 xx 10^(11)`

C

`4.42 xx 10^(-15)`

D

`4.42 xx 10^(-18)`

Text Solution

Verified by Experts

The correct Answer is:
D
`E = hv = (hc)/(lamda)`. Given `lamda = 45 nm = 45 xx 10^(-9) m`
`:. E = ((6.63 xx 10^(-34) Js) (3 xx 10^(8) ms^(-1)))/((45 xx 10^(-9) m))`
`= 4.42 xx 10^(-18) J`
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Knowledge Check

  • Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A
    `6.67xx10^(12)`
    B
    `4.42xx10^(-13)`
    C
    `4.42xx10^(-18)`
    D
    `6.67xx10^(12)`

  • Calculate the energy in joule corresponding to light of wavelength 45 nm (Planck.s constant h=6.63xx10^(-34) Js, speed of light c=3xx10^(8) ms^(-2))

    A
    `6.67xx10^(12)`
    B
    `4.42xx10^(-13)`
    C
    `4.42xx10^(-18)`
    D
    `6.67xx10^(12)`

  • The energy of a photon wavelength k = 1 meter is (Planck's constant = 6.625 xx 10^(-34) Js, speed of light = 3 xx 10^(8) m//s )

    A
    `1.988 xx 10^(-23) J`
    B
    `1.988 xx 10^(-28) J`
    C
    `1.988 xx 10^(-30) J`
    D
    `1.988 xx 10^(-25) J`

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