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Assertion. The plots of probability dens...

Assertion. The plots of probability density and radial probability function versus distance r from the nucleus for any particular orbital are not identical
Reason. Probability density is `Psi^(2)` whereas radial probability function represents probability of finding the electron in a shell of thickness `dr`.

A

If both assertion and reason are true, and reason is the true explanation of the assertion

B

If both assertion and reason are true, but reason is not the true explanation of the assertion

C

If assertion is true, but reason is false

D

If both assertion and reason are false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the assertion and reason provided: **Assertion:** The plots of probability density and radial probability function versus distance \( r \) from the nucleus for any particular orbital are not identical. **Reason:** Probability density is \( \Psi^2 \) whereas radial probability function represents the probability of finding the electron in a shell of thickness \( dr \). ### Step-by-Step Solution: 1. **Understanding Probability Density:** - Probability density for an electron in an orbital is given by the square of the wave function, \( \Psi^2 \). This function describes the likelihood of finding an electron at a specific point in space. - The plot of \( \Psi^2 \) versus distance \( r \) from the nucleus shows how the probability density changes with distance. **Hint:** Remember that \( \Psi^2 \) gives the probability density at a point in space. 2. **Understanding Radial Probability Function:** - The radial probability function, on the other hand, is defined as \( 4\pi r^2 \Psi^2 \). This function accounts for the volume element in spherical coordinates, which is important because electrons can be found in any direction around the nucleus. - The radial probability function represents the probability of finding an electron within a spherical shell of thickness \( dr \) at a distance \( r \) from the nucleus. **Hint:** The radial probability function incorporates the geometry of space, which is why it includes the factor \( 4\pi r^2 \). 3. **Comparing the Two Functions:** - When we plot both \( \Psi^2 \) and \( 4\pi r^2 \Psi^2 \) against \( r \), we will see that the shapes of these plots are different. The probability density plot shows how likely it is to find an electron at a specific point, while the radial probability function shows how likely it is to find the electron within a spherical shell. - Therefore, the assertion that these plots are not identical is correct. **Hint:** Visualize the graphs: one is a function of distance, while the other is a function of the volume around that distance. 4. **Evaluating the Reason:** - The reason provided states that probability density is \( \Psi^2 \) and that the radial probability function represents the probability of finding the electron in a shell of thickness \( dr \). This statement is accurate and correctly explains why the two plots differ. - Thus, the reason supports the assertion. **Hint:** Check if the reason logically follows from the assertion. 5. **Conclusion:** - Both the assertion and the reason are true, and the reason correctly explains the assertion. Therefore, the correct answer is that both the assertion and reason are true, and the reason is the correct explanation for the assertion. **Final Answer:** Both the assertion and reason are true, and the reason is the correct explanation for the assertion.

To solve the question, we need to analyze the assertion and reason provided: **Assertion:** The plots of probability density and radial probability function versus distance \( r \) from the nucleus for any particular orbital are not identical. **Reason:** Probability density is \( \Psi^2 \) whereas radial probability function represents the probability of finding the electron in a shell of thickness \( dr \). ### Step-by-Step Solution: ...
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Knowledge Check

  • The zero probability of finding the electron in d_(x^2 - y^2) orbital is

    A
    on two opposite side of nucleus along x-axis.
    B
    in the nucleus
    C
    same on all the sides around the nucleus.
    D
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  • The zero probability of finding the electron in d_(x^2 - y^2) orbital is

    A
    on two opposite side of nucleus along x-axis.
    B
    in the nucleus
    C
    same on all the sides around the nucleus.
    D
    None of these
  • The zero probability of finding the electron in d_(x^2 - y^2) orbital is

    A
    on two opposite side of nucleus along x-axis.
    B
    in the nucleus
    C
    same on all the sides around the nucleus.
    D
    None of these
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    The Schrodinger wave equation for H-atom is nabla^(2) Psi = (8pi^(2)m)/(h^(2)) (E-V) Psi = 0 Where nabla^(2) = (del^(2))/(delx^(2)) +(del^(2))/(dely^(2)) +(del^(2))/(delz^(2)) E = Total energy and V=potential energy wave function Psi_(((r, theta,phi)))R_((r))Theta_((theta))Phi_((phi)) R is radial wave function which is function of ''r'' only, where r is the distance from nucleus. Theta and Phi are angular wave function. R^(2) is known as radial probability density and 4pir^(2)R^(2)dr is known as radial probability function i.e., the probability of finding the electron is spherical shell of thickness dr. Number of radial node =n -l - 1 Number of angular node = l For hydrogen atom, wave function for 1s and 2s-orbitals are: Psi_(1s) = sqrt((1)/(pia_(0)^(a)))e^(-z_(r)//a_(0)) Psi_(2s) = ((Z)/(2a_(0)))^(½) (1-(Zr)/(a_(0)))e^(-(Zr)/(a_(0))) The plot of radial probability function 4pir^(2)R^(2) aganist r will be: Answer the following questions: The following graph is plotted for ns-orbitals The value of 'n' will be:

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