Styrene (C(6)H(5)CH=CH(2)) is treated w...

Styrene `(C_(6)H_(5)CH=CH_(2))` is treated with HBr presence of peroxides.

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To solve the problem of what happens when styrene (C₆H₅CH=CH₂) is treated with HBr in the presence of peroxides, we can follow these steps: ### Step 1: Understand the Reaction Conditions Styrene is an alkene, and when it reacts with HBr in the presence of peroxides, we are dealing with a radical addition reaction. The presence of peroxides initiates a free radical mechanism that alters the typical Markovnikov addition pattern. **Hint:** Remember that the presence of peroxides changes the regioselectivity of the addition reaction. ### Step 2: Identify the Structure of Styrene ...

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C_(6)H_(5)-CH=CH-CHO is

Benzaldehyde

Salicylaldehyde

Cinamaldehyde

None of these.

Which of the following compound is produced when CH_2=CH-(CH_2)_2COOH reacts with HBr in presence of peroxides

`CH_3CH(CH_2)_5COOH`

`BrCH_2CH_2(CH_2)_2COOH`

`CH_3CH_2CH_2(CH_2)_5COOH`

`CH_3CH_2BrCH_2CH_2COOH`

An alkene CH_(3)CH = CH_(2) is treated with B_(2)H_(6) in presence of H_(2)O_(2) . The final product formed is

`CH_(3)CH_(2)CHO`

`CH_(3)CH(OH)CH_(3)`

`CH_(3)CH_(2)CH_(2) OH`

`(CH_(3)CH_(2)CH_(2))_(3)B`