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Compound X on reduction with LiAlH(4) ...

Compound X on reduction with `LiAlH_(4)` gives a hydride Y containing `21.72%` hydrogen along with other products. The compound Y reacts with air explosively resulting in boron trioxide. Identify X and Y. Give balanced equations involved in the formation of Y and its reaction with air. Drew the structure of Y.

Text Solution

AI Generated Solution

To solve the problem, we need to identify the compounds X and Y, provide the balanced equations for their formation and reactions, and draw the structure of Y. ### Step 1: Identify Compound Y Given that compound Y contains 21.72% hydrogen, we can calculate its molecular formula. The percentage of hydrogen in a compound can be calculated using the formula: \[ \text{Percentage of H} = \left( \frac{\text{mass of H}}{\text{molar mass of compound}} \right) \times 100 \] ...
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Compound X on reduction with LiAlH_(4) gives a hydride Y containing 21.72% hydrogen along with other products. The compound Y reacts with air explosively resulting in boron trioxide. Identify X and Y. Give balanced reactions involved in the formation of Y and its reaction with air. Draw the structure of Y.

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Knowledge Check

  • Compound X on reduction with LiAlH_(4) gives a hydride Y containing 21.72% hydrogen and other products. The compound Y reacts with air expolosively resulting in boron trioxide. What are X and Y respectively ?

    A
    `BCl_(3), B_(2)H_(6)`
    B
    `PCl_(3), B_(2)H_(6)`
    C
    `B_(2)H_(6), BCl_(3)`
    D
    `LiAlH_(4),PCl_(3)`

  • Compound (X) on reduction with LiAlH_(4) given a hydride (Y) containing 21.72\% hydrogen along with other products. The compound (Y) reacts with air explosively resulting in boron trioxide. Compound x and Y are respectively

    A
    `BCl_(2), B_(2)H_(6)`
    B
    `B_(2)H_(6), BCl_(3)`
    C
    `BF_(3),Al_(2)O_(6)`
    D
    `B_(2)H_(6),BF_(3)`

  • When chlorine reacts with a gas X, an explosive inorganic compound Y is formed. Then X and Y will be :

    A
    X=`O_(2)` and Y=`NCl_(3)`
    B
    `X=NH_(3)` and `Y=NCl_(3)`
    C
    X=`O_(2)` and `Y=NH_(4)Cl`
    D
    `X=NH_(3)` and `Y=NH_(4)Cl`