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A bcc lattic is made up of hollow sphere...

A bcc lattic is made up of hollow spheres of X. spheres of soldid 'Y,' are present in hollow spheres of X. The radius of 'Y' is half of the radius of 'X' . Calculate the ratio of the total volume of spherees of 'X' unoccupied by Y in a unit cell and volume of the unit cell ?

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To solve the problem, we need to calculate the ratio of the total volume of spheres of 'X' unoccupied by 'Y' in a unit cell to the volume of the unit cell. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Geometry of the BCC Lattice In a body-centered cubic (BCC) lattice, there are 2 effective atoms per unit cell. The atoms at the corners contribute 1/8th of their volume to the unit cell, and the atom at the center contributes fully. ### Step 2: Define the Radii Let the radius of hollow sphere 'X' be \( R \). The radius of solid sphere 'Y' is given as half of that, so: - Radius of \( Y = \frac{R}{2} \) ...
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A bcc lattice is made up of hollow spheres of X. Spheres of solid 'Y' are present in hollow spheres of X. The radius of 'Y' is half of the radius of 'X' . Calculate the ratio of the total volume of spheres of 'X' unoccupied by Y in a unit cell and volume of the unit cell ?

A bcc lattice is made up of hollow spheres of B . Spheres of solids A are present in hollow spheres of B . The radius of A is half of the radius of B . The ratio of total volume of spheres of B unoccupied by A in a unit cell and volume of unit cell is A xx (pisqrt(3))/(64) . Find the value of A .

Knowledge Check

  • If the radius of a sphere is doubled, what is the ratio of the volume of the first sphere to that of the second?

    A
    `2:8`
    B
    `1:2`
    C
    `1:3`
    D
    `1:8`
  • If the radius of a sphere is 3 cm, then ratio of its surface area and volume is

    A
    `1:1`
    B
    `1:3`
    C
    `3:2`
    D
    `1:2`
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