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The equation of trajectory of a projecti...

The equation of trajectory of a projectile thrown from a level ground near the surface of earth is given by y = ax `- bx^(2)` , with y axis in vertical direction and x-axis in horizontal direction .a and b are constants. Then

A

The range of the projectile is ` a/b`

B

At ` x = a/(2b)` , the velocity of projectile becomes zero

C

The maximum height attained by projectile is ` a^(2)/(4b)`

D

The angle of projection is ` tan^(-1)(a)`

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The correct Answer is:
A, C, D
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