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A particle moves with decreasing speed a...

A particle moves with decreasing speed along the circle of radius R so that at any moment of time its tangential and centripetal accelerations are equal in magnitude. At the initial moment , t =0 its speed is u.

The time after which the speed of particle reduces to half of its initial value is

A

`(2R)/u`

B

`R/u`

C

`R/(2u)`

D

`(3R)/(2u)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A particle moves with deceleration along the circle of radius R so that at any moment of time its tangential and normal acceleration are equal in moduli. At the initial moment t=0 the speed of the particle equals v_(0) , then th speed of the particle as a function of the distance covered S will be

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    `v=v_(0) e^(R//S)`
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  • A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is

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    `2pi v//T`
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