The correct order of liquefaction of the gases `NH_(3),CO_(2),SO_(2)` and HCl is

Options

A. `NH_(3) gt CO_(2) gt HCl gt SO_(2)`
B. `CO_(2) gt NH_(3) gt SO_(2) gt HCl_(2)`
C. `HCl gt CO_(2) gt NH_(3) gt SO_(2)`
D. `SO_(2) gt NH_(3) gt HCl gt CO_(2)`

Explanation

To determine the correct order of liquefaction of the gases NH₃, CO₂, SO₂, and HCl, we need to consider their critical temperatures. The liquefaction of gases is inversely proportional to their critical temperatures, meaning that a gas with a higher critical temperature will liquefy more easily than a gas with a lower critical temperature.

### Step-by-Step Solution:

1. **Understand Critical Temperature**:
- The critical temperature of a gas is the maximum temperature at which it can be liquefied by applying pressure. Above this temperature, the gas cannot be liquefied, regardless of the pressure applied.

2. **List the Critical Temperatures**:
- We need to find the critical temperatures for each of the gases:
- NH₃ (Ammonia): 406 K
- CO₂ (Carbon Dioxide): 304 K
- SO₂ (Sulfur Dioxide): 430 K
- HCl (Hydrochloric Acid): 324 K

3. **Compare the Critical Temperatures**:
- Now, we will compare the critical temperatures:
- SO₂: 430 K (highest)
- NH₃: 406 K
- HCl: 324 K
- CO₂: 304 K (lowest)

4. **Determine the Order of Liquefaction**:
- Since liquefaction is inversely proportional to critical temperature, the gas with the highest critical temperature will liquefy first. Therefore, the order of liquefaction from easiest to hardest is:
- SO₂ > NH₃ > HCl > CO₂

5. **Final Answer**:
- The correct order of liquefaction of the gases is: SO₂, NH₃, HCl, CO₂.