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The variation of vapour pressure with te...

The variation of vapour pressure with temperature for a liquid was studied by plotting log P versus 1/T as shown in the Fig. The slope of the line `(tan theta)` was found to be -2 K. Then latent heat of vaporisation of the given liquid is

A

`4.606" cal mol"^(-1)`

B

`2.303" cal mol"^(-1)`

C

`9.212" cal mol"^(-1)`

D

`8.314" cal mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
According to Clausis-Clapeyron equation,
`log P=logA-(Delta_("vap")H)/(2.303"RT")`
Thus, plot of log P vs `(1)/(T)` is a straight line with slope `=-(Delta_("vap")H)/(2.303"R")=-2R` (Given). Hence,
`Delta_("vap")H=2xx2.303xx2"cal "K^(-1)`
`=9.212"cal"mol^(-1)`
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Knowledge Check

  • The graph between the log K versus 1/T is a straight line. The slope of the line is

    A
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