`1 cm^(3)` of 0.01 N HCl solution is added to one litre of sodium chloride solution . Calculate the pH of the resulting solution.

Explanation

As NaCl solution is neutral, it simply dilutes the HCl solution from 1 cc to 1000 cc.
Now `[H^(+)]=0.01//1000=10^(-5)M :. pH = 5`.