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Lead chloride has a solubility product ...

Lead chloride has a solubility product of `1.7xx10^(-5)` at 298 K. Calculate its solubility at this temperature.

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To calculate the solubility of lead chloride (PbCl₂) given its solubility product (Ksp) at 298 K, we can follow these steps: ### Step-by-Step Solution: 1. **Write the Dissociation Equation**: Lead chloride (PbCl₂) dissociates in water as follows: \[ \text{PbCl}_2 (s) \rightleftharpoons \text{Pb}^{2+} (aq) + 2 \text{Cl}^- (aq) ...
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Knowledge Check

  • If for a binary weak electrolyte the solubility product is 4xx10^(-10) at 298K.Calculate its solubility is mol dm^(-3) at the same temperature

    A
    `4xx10^(-5)`
    B
    `2xx10^(-5)`
    C
    `8xx10^(-10)`
    D
    `16xx10^(-20)`

  • The solubility product of chalk is 9.3xx10^(-8) . Calculate its solubility in gram per litre

    A
    `0.3040 gram//litre`
    B
    `0.0304 gram//litre`
    C
    `2.0304 gram//litre`
    D
    `4.0304 gram//litre`

  • If solubility product of HgSO_(4) is 6.4 xx 10^(-5) , then its solubility is

    A
    `8 xx 10^(-3)` mole/litre
    B
    `6.4 xx 10^(-5)` mole/litre
    C
    `6.4 xx 10^(-3)` mole/litre
    D
    `2.8 xx 10^(-6)` mole/litre

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    Solubility product of AgCl is 1 xx 10^(-6) at 298 K. Its solubility in mole "litre"^(-1) would be

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