Lead chloride has a solubility product of `1.7xx10^(-5)` at 298 K. Calculate its solubility at this temperature.

Explanation

To calculate the solubility of lead chloride (PbCl₂) given its solubility product (Ksp) at 298 K, we can follow these steps:

### Step-by-Step Solution:

1. **Write the Dissociation Equation**:
Lead chloride (PbCl₂) dissociates in water as follows:
\[
\text{PbCl}_2 (s) \rightleftharpoons \text{Pb}^{2+} (aq) + 2 \text{Cl}^- (aq)
...