Calculate the electrode potential of a copper wire dipped in `"0.1M CuSO"_(4)` solution at `025^(@)C`. The standard electrode potential of copper is 0.34 Volt.

Explanation

The electrode reaction written as reduction reaction is
`Cu^(2+) +2e^(-)toCu` so that n=2
Applying nernst eqn. we get `E=E^(@)-(0.0591)/(2)"log"(1)/([Cu^(2+)])`
`=0.34-(0.0591)/(2)"log"(1)/(0.1)=0.34-0.02955=0.31045`volt.