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The molar conductivity of KCl solution a...

The molar conductivity of `KCl` solution at different concentrations at `298 K` is given below `:`
`{:(c or M (mol L^(-1)),wedge_(m)(Scm^(2)mol^(-1))),(0.000198,148.61),(0.000309,148.29),(0.000521,147.81),(0.000989,147.09):}`
Show that a plot between `wedge_(m)` and `sqrt(c)` is a straight line. Determine the value of `wedge_(m)^(@)` and `A` for `KCl` .

Text Solution

Verified by Experts

Taking the square root of concentration, we obtain
`{:(c^(1//2)(mol" "L^(-1))^(1//2),wedge_(m)//S" "cm^(2)mol^(-1)),(0.01407,148.61),(0.01758,148.29),(0.02283,147.81),(0.03154,147.09):}`

A plot of `wedge_(m)` (y-axis) and `c^(1//2)` (x-axis) is shown in the adjoining fig:
It can be seen that it is nearly a straight line. from the intercept (i.e., when `c^(1//2)=0`), we find that
`wedge_(m)^(@)=150.0" S "cm^(2)mol^(-1)`
and `A=-"slope"=(Deltay)/(Deltax)=(150.0-147.0)/(0.034)`
`=88.23" S "cm^(2)mol^(-1)//(mol//L^(-1))^(1//2)`.
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Knowledge Check

  • Molar conductivity of 0.15 M solution of KCI at 298 K, if its conductivity is 0.0152 S cm^(-1) will be

    A
    `124 Omega^(-1) "cm"^(2) "mol"^(-1)`
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    C
    `101 Omega^(-1) "cm"^(2) "mol"^(-1)`
    D
    `300 Omega^(-1) "cm"^(2) "mol"^(-1)`
  • Calculate molar conductivity of 0.15 M solution of KCl at 298 K if its conductivity is 0.0152 S cm^(-1)

    A
    `124 Omega^(-) cm^(2)"mol"^(-1)`
    B
    `204 Omega^(-1) cm^(2)"mol"^(-1)`
    C
    `101 Omega^(-1)cm^(2)"mol"^(-1)`
    D
    `30 Omega^(-1) cm^(2)"mol"^(-1)`
  • Calculate molar conductivity of 0.15 M solution of KCl at 298 K if its conductivity is 0.0152 S cm^(-1)

    A
    `124 Omega^(-) cm^(2)"mol"^(-1)`
    B
    `204 Omega^(-1) cm^(2)"mol"^(-1)`
    C
    `101 Omega^(-1)cm^(2)"mol"^(-1)`
    D
    `30 Omega^(-1) cm^(2)"mol"^(-1)`
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