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Given below are the half -cell reactions...

Given below are the half -cell reactions
`Mn^(2+)+2e^(-) to Mn, E^(@)=-1.18V`
`Mn^(3+)+e^(-) to Mn^(2+), E^(@)=+1.51 V`
The `E^(@)` for `3Mn^(2+)to Mn+2Mn^(3+)` will be _________.

A

`-0.33V`, the reaction will occur

B

`-2.69V`, the reaction will not occur

C

`-2.69V`, the reaction will occur

D

`-0.33V`, the reaction will not occur

Text Solution

Verified by Experts

The correct Answer is:
C
The given cell reaction can be obtained from half-cell reactions as under:
`Mn^(2+)+2e^(-)toMn,E^(@)=-1.18V`
`underline(" "2Mn^(2+)to2Mn^(3+)+2e^(-),E^(@)=-1.51V)`
Overall reaction:
`3Mn^(2+)toMn+2Mn^(3+),E^(@)=-1.18V+(-1.51)`
`=-2.69V`
As `E_(cell)^(@)` is -ve, reaction will not occur.
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अर्ध -सेल अभिक्रियांए निम्न है - Mn^(2+) + 2e^(-) to Mn, E^(@) = -1.18 V 2(Mn^(3+) + e^(-) to Mn^(2+)), E^(@) = +1.51 V 3Mn^(2+) to Mn + 2Mn^(3+) के लिए मान होगा

Knowledge Check

  • Given below are the half-cell reactions ltbr Mn^(2+)+2e^(-)toMn,E^(@)=-1.18V 2(Mn^(3+)+e^(-)toMn^(2+)),E^(@)=+1.51V The E^(@) for 3Mn^(2+)toMn+2Mn^(3+) will be:

    A
    `-2.69V`, the reaction will not occur
    B
    `-2.69V`, the reaction will occur
    C
    `-0.33V`, the reaction will not occur
    D
    `-0.33V`, the reaction will occur

  • Given below are half-cell reaction: Mn^(2+)+2e^(-) rarr Mn,, E^(@) = -1.18 V 2(Mn^(3+)+e^(-) rarr Mn^(2+)),, E^(@) = +1.51 V The E^(@) for 3Mn^(2+) rarr Mn+2Mn^(3+) will be:

    A
    `-0.33 V`, the reaction will not occur
    B
    `-0.33 V`, the reaction will occur
    C
    `-2.69 V`, the reaction will not occur
    D
    `-2.69 V`, the reaction will occur

  • Given below are the half -cell reactions Mn^(2+) + 2e^(-) rarr Mn, E^@ =- 1. 18 V 2 (Mn^(3+) = E^(-) rarr Mn^(2+)). E^@ = + 1.5 V The E^@ for Mn^(2+) rarr Mn+ 2 Mn^(3+) will be.

    A
    `-2.69 V`, the reaction will not will not occur
    B
    ` -2 . 69 V`, the reaction will occur
    C
    ` -0. 33 V`, the reaction will not occur
    D
    ` -0. 33 V` the reaction will occur

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