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Calculate the stability constant of the ...

Calculate the stability constant of the complex `[Zn(NH_(3))_(4)]^(2+)` formed in the reaction
`Zn^(2+)+4NH_(4)hArr[Zn(NH_(3))_(4)]^(2+)`.
Given that `E_(Zn^(2+)//Zn)^(@)=-0.76V and E_((Zn(NH_(3))_(4)]^(2+))^(@)//Zn,4NH_(3))^(@)=-1.03V`

Text Solution

AI Generated Solution

To calculate the stability constant of the complex \([Zn(NH_3)_4]^{2+}\), we will follow these steps: ### Step 1: Write the half-reactions We have two half-reactions based on the given standard reduction potentials: 1. For the reduction of \(Zn^{2+}\) to \(Zn\): \[ Zn^{2+} + 2e^- \rightarrow Zn \quad (E^\circ = -0.76 \, V) \] ...
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The EAN of Zn in [Zn(NH_(3))_(4)]^(2+) is

Calculate the equilibrium constant for the reaction at 298K. Zn(s) +Cu^(2+)(aq) hArr Zn^(2+)(aq) +Cu(s) Given, E_(Zn^(2+)//Zn)^(@) =- 0.76V and E_(Cu^(2+)//Cu)^(@) = +0.34 V

Knowledge Check

  • What is the effective atomic number of Zn (30) in Zn(NH_(3))_(4)Cl_(2) ?

    A
    36
    B
    54
    C
    86
    D
    118
  • Use the Standard Reduction Potentials given below to calculate K_(f) for [Zn(NH_(3))_(4)]^(+2) at 25^(@) . Zn^(2+)(aq)+4NH_(3)(aq)ifZn(NH_(3))_(4)^(2+)(aq) [Zn(NH_(3))_(4)]^(+2)+2e^(-)iffZn(s)+4NH_(3)(aq), E^(@)=-1.04V , Zn^(2+)(aq)+2e^(-)iffZn(s), E^(@)=-0.76V

    A
    `6 xx 10^(18)`
    B
    `3 xx 10^(9)`
    C
    `2 xx 10^(6)`
    D
    `3 xx 10^(-9)`
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