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Which out of the two, La(OH)(3) and Lu(O...

Which out of the two, `La(OH)_(3)` and `Lu(OH)_(3)` is more basic and why ?

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To determine which of the two compounds, La(OH)₃ (lanthanum hydroxide) or Lu(OH)₃ (lutetium hydroxide), is more basic, we can analyze their properties based on the concepts of basicity and covalent character. ### Step-by-Step Solution: 1. **Understanding Basicity**: Basicity refers to the ability of a compound to accept protons (H⁺ ions) or donate electron pairs. In the context of metal hydroxides, basicity can be influenced by the nature of the metal cation. 2. **Position in the Lanthanide Series**: Lanthanum (La) is located at the beginning of the lanthanide series, while lutetium (Lu) is at the end. As we move from La to Lu, the ionic character of the metal hydroxides tends to decrease. ...
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(a). Of the lanthanides, cerium (Z=58) forms a tetrapositive ion, Ce^(4+) in aqueous solution. Why? (b), The +3 oxidation states of lanthanum (Z=57) , gadolinium (Z=64) and lutetium (Z=71) are especially stable. Why? (c). Why Zr and or Nb anbd Ta exhibit similar properties ? (d). Which oiut of the two La(OH)_3 and Lu(OH)_3 , is more basic and why?

Why Ce(OH)_(3) is more basic than Lu(OH)_(3) ?

Knowledge Check

  • La^(3+) and Lu^(3+) are

    A
    Both paramagnetic
    B
    Both diamagnetic
    C
    `La^(3+)` is diamagnetic and `Lu^(3+)` paramagnetic
    D
    None of these

  • Among the lanthanides, La^(3+) and Lu^(3+) ions are

    A
    paramagnetic
    B
    diamagnetic
    C
    ferromagnetic
    D
    all of these

  • Fe(OH)_3 and Cr(OH)_3 precipitates are separated by

    A
    `Ag.NH_3`
    B
    HCI
    C
    `NaOH//H_2O_2`
    D
    `H_2SO_4`

    • Similar Questions

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    Which is more basic La(OH)_(3) or Lu(OH)_(3) ? Why ?

    Which is more basic La (OH)_(3) or Lu (OH)_(3) ? Why

    Lanthanoids and actinoids are f-block elements in which the last electron enters the anti-penultimate energy level. The most common oxidation state of lanthanoids is +3, though +2 and +4 oxidation states are exhibited by some of the elements. In lanthanoid series, there is a progressive decrease in atomic and ionic radii, known as lanthanoid contraction. Unlike lanthanoids, actinoids show a large number of oxidation states. Which out of La(OH)_3 and Lu(OH)_3 is more basic?

    Out of CH_(3)CO O^(-) and OH^(-) which is stronger base and why ?

    Explain the following : (a) Out of Sc^(3+), Co^(2+) " and "Cr^(3+) "ions, only "Sc^(3+) is colourless in aqueous solutions. (Atomic no.: Co =27, Sc = 21 and Cr =24) (b) The E^(@)Cu^(2+)//Cu for copper metal is positive (+0.34), unlike the remaining members of the first transition series. (c) La(OH)_(3) " is more basic than Lu "(OH)_(3).

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