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Silver atom has completely filled d orbi...

Silver atom has completely filled `d` orbitals `(4d^(10))` in its ground state. How can you say it is a transition element?

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The outer electronic configuration of `Ag(Z = 47)` is `4d^(10) 5s^(1)` .In addition to `+1` , it shows an oxidation state of `+2` ( e.g., `AgO` and `AgF_(2)` exist ) . In `+2` oxidation state, the configuration is `d^(9)` , i.e., the d-subshell is incompletely filled. Hence, it is a transition element.
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Explain the following terms : (a) Chemistry of all Lanthanoids is so identical . (b) Silver atom has completely filled d- orbitals (4d^(10)) in its ground state . How can you say that is a transition elements ?

Silver atom has completely filled d-orbitals (4d^(10)) in its ground state. How can you say that it is a transition element ?

Knowledge Check

  • a completely filled d orbital (d^(10))

    A
    Spherically symmetrical
    B
    Has octahedral symmetrical
    C
    Has octahedral symmetry
    D
    Depends on the atom

  • A completely filled d-orbital (d^10) is

    A
    Spherically symmetrical
    B
    has octahedral symmetry
    C
    Has tetrahedral symmetry
    D
    Depends on the atom

  • Statement-1: silver is a transition element. Statement-2: silver atom has completely filled d-robitals (4d^(10)) in its ground state.

    A
    Statement-1 is true, statement-2 is true, statement-2 is a correct explanation for statement-1.
    B
    Statement-1 is true, statement-2 is true, statement-2 is NOT a correct explanation for statement-1
    C
    Statement-1 is true, statement-2 is false.
    D
    statement-1 is false, statement-2 is true.

    • Similar Questions

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    (a) Silver atom has completely filled 'd' orbitals (4d^10) in its ground state. How can you say that it is a transition element ? (b) Actinoids exhibit a large number of oxidation states in comparison to corresponding members of Lanthanoid series. Why?

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