Home
Class 12
CHEMISTRY
How would you account for the fact that ...

How would you account for the fact that actinoids exhibit a larger number of oxidation state than the corresponding lanthanoids?

Text Solution

Verified by Experts

Actinoids show a larger number of oxidation states because the energy gap between 5f, 6d and 7s subhsells is very small and hence all the electrons present in these subshells can participate in bonding whereas lanthanoids show a limited number of oxidation states because the energy gap between 4f and 5d subshells is large and all the electrons in these subshells cannot participate in bonding.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise NCERT (QUESTIONS AND EXERCISES WITH ANSERS)|10 Videos

  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise NCERT INTEXT UNSOLVED QUESTIONS|10 Videos

  • D- AND F-BLOCK ELEMENTS

    PRADEEP|Exercise TEST YOUR GRIP( FILL IN THE BLANKS)|33 Videos

  • CORDINATION COMPOUNDS

    PRADEEP|Exercise Important Questions|28 Videos

  • ELECTROCHEMISTRY

    PRADEEP|Exercise IMPORTANT QUESTIONS FOR BOARD EXAMINATION|25 Videos

Similar Questions

Explore conceptually related problems

Explain the following observations : (i) Many of the transition elements are known to form interstitial compounds . (ii) There is a general increase in density from titanium (Z =22) to copper (Z = 29). (iii) The members of the actinoid series exhibit a larger number of oxidation states than the corresponding members of the lanthanoid series.

Explain the following observations: (i) Many of the transition elements are known to form interstitial compounds. (ii) There is a general increase in density from titanium (Z = 22) to copper (Z = 29). (iii) The members of the actinoid series exhibit a larger number of oxidation states than the corresponding members of the lanthanoid series.

Knowledge Check

  • The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because

    A
    the 5f orbitals extend further from the nucleus than the 4f orbitals
    B
    the 5f orbitals are more buried than the 4f orbitals
    C
    there is a similarity between 4f and 5f orbitals in their angular part of the wave function
    D
    the actinoids are more reactive than the lanthanoids.

  • The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because

    A
    the 5f orbitals are more buried than the 4f orbitals
    B
    there is a similarly between 4f and 5f orbitals in their angular part of the wave function
    C
    the actinoids are more reactive than the lanthanoids
    D
    the 5f orbitals extend farther from the nucleus than the 4f orbitals

  • The actinoids exhibit, more member of oxidation states in general than the lanthanoids. This is because

    A
    the actinides are more reactive than the lanthanides
    B
    the `5f`-orbits are more buried than the `4f`-orbits
    C
    there is a similarity between `4f`and `5f`-orbits in their angular part of the wave function.
    D
    the `5f`-orbits extend farther from the nucleus than the `4f`-orbitals.

    • Similar Questions

    Explore conceptually related problems

    How would you account for the following ? (i) With the same d-orbital configuration (d^(4)) Cr^(2+) is reducting agent while Mn^(3+) is an oxidizing agent. (ii) The actionoids exhibits a larger numbe of oxidation states than the corresponding members in the lanthanoid series. (iii) Most of the transition metal ions exhibit characteristic in colours in aqueous solutions.

    How will you account for the following: (a) Actinoids exhibit more number of oxidation states than lanthanoids. (b) Atomic radii of second and third transition series elements are almost identical.

    The actinoids exihibits more number of oxidation states in general than the lanthanoids.This is because

    (a) Silver atom has completely filled 'd' orbitals (4d^10) in its ground state. How can you say that it is a transition element ? (b) Actinoids exhibit a large number of oxidation states in comparison to corresponding members of Lanthanoid series. Why?

    Which of the following exhibit minimum number of oxidation states

    Home
    Profile