For the first row transition metals the ...

For the first row transition metals the `E^(ɵ)` value are:
`{:(underset(-1.18)(V),,underset(-0.91)(Cr),,underset(-1.18)(Mn),,underset(-0.44)(Fe),,underset(-0.28)(Co),,underset(-0.25)(Ni),underset(+0.34)(Cu)):}`
Explain the irregularity in the above values.

Text Solution

Verified by Experts

This is because `E^(@)` values are the sum of sublimation enthalpy , ionization enthalpy , hydration enthalpy etc. The irregularity is due to the irregular variation of ionization enthalpies `(IE_(1)+IE_(2))` and also the sublimation enthalpies which are relatively much lower for Mn `( 240 kJ mol^(-1))` and `V ( 470 kJ mol^(-1))`

Topper's Solved these Questions

D- AND F-BLOCK ELEMENTS
PRADEEP|Exercise NCERT INTEXT UNSOLVED QUESTIONS|10 Videos
D- AND F-BLOCK ELEMENTS
PRADEEP|Exercise NCERT EXERCISES|37 Videos
D- AND F-BLOCK ELEMENTS
PRADEEP|Exercise CONCEPTUAL QUESTIONS|56 Videos
CORDINATION COMPOUNDS
PRADEEP|Exercise Important Questions|28 Videos
ELECTROCHEMISTRY
PRADEEP|Exercise IMPORTANT QUESTIONS FOR BOARD EXAMINATION|25 Videos

(A) overset(NaNO_(2)//HCl)underset((ii)H_(2)//Ni)underset(0-5^(@))(rarr)(B) , is:

Student I ,II , and III perform an experiment for measuring the acceleration due to gravity (g) usinf a simple pendulum. They use lengths of the pendulum and // or record time for different number of oscillations . The observations are shown in the following table . Least count for length = 0.1 cm {:(underset(III)underset(II)underset(I)underset()underset()("Student"),underset(20.0)underset(64.0)underset(64.0)underset((cm))underset("Pendulam")("Length of "),underset(4)underset(4)underset(8)underset((n))underset("n Oscillation")("Number of"),underset(9.0)underset(16.0)underset(16.0)underset((s))underset("Period")("Time")):} Least count for time = 0.1 s . If E_(I), E_(II) , and E_(III) are the percentage errors in g , i.,e., ((Delta g)/( g) xx 100) for students I,II , and III, respectively , then

`E_(I) = 0`

` E_(I) is minimum`

`E_(I) = E_(II)`

`E_(II) is maximum`

If overset(a)underset(0) int f(2a-x)dx = m and overset(a)underset(0)int f(x) dx=n , then overset(2a)underset(0) int f(x) dx is equal to

`2m+n`

`m+2n`

`m-n`

`m+n`

For the first row transition metals the `E^(ɵ)` value are:
`{:(underset(-1.18)(V),,underset(-0.91)(Cr),,underset(-1.18)(Mn),,underset(-0.44)(Fe),,underset(-0.28)(Co),,underset(-0.25)(Ni),underset(+0.34)(Cu)):}`
Explain the irregularity in the above values.

Text Solution

Topper's Solved these Questions

Similar Questions

Knowledge Check

(A) overset(NaNO_(2)//HCl)underset((ii)H_(2)//Ni)underset(0-5^(@))(rarr)(B) , is:

If overset(a)underset(0) int f(2a-x)dx = m and overset(a)underset(0)int f(x) dx=n , then overset(2a)underset(0) int f(x) dx is equal to

Similar Questions

PRADEEP-D- AND F-BLOCK ELEMENTS-NCERT (QUESTIONS AND EXERCISES WITH ANSERS)

For the first row transition metals the `E^(ɵ)` value are: `{:(underset(-1.18)(V),,underset(-0.91)(Cr),,underset(-1.18)(Mn),,underset(-0.44)(Fe),,underset(-0.28)(Co),,underset(-0.25)(Ni),underset(+0.34)(Cu)):}` Explain the irregularity in the above values.

Text Solution

Topper's Solved these Questions

Similar Questions

Knowledge Check

(A) overset(NaNO_(2)//HCl)underset((ii)H_(2)//Ni)underset(0-5^(@))(rarr)(B) , is:

If overset(a)underset(0) int f(2a-x)dx = m and overset(a)underset(0)int f(x) dx=n , then overset(2a)underset(0) int f(x) dx is equal to

Similar Questions

PRADEEP-D- AND F-BLOCK ELEMENTS-NCERT (QUESTIONS AND EXERCISES WITH ANSERS)

For the first row transition metals the `E^(ɵ)` value are:
`{:(underset(-1.18)(V),,underset(-0.91)(Cr),,underset(-1.18)(Mn),,underset(-0.44)(Fe),,underset(-0.28)(Co),,underset(-0.25)(Ni),underset(+0.34)(Cu)):}`
Explain the irregularity in the above values.