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Oxidation state of potassium in K2O, K2O...

Oxidation state of potassium in K2O, K2O2 & KO2 are respectively

A

`+1, +1, +1`

B

`+1, +2, +4`

C

`+1, +2, +2`

D

`+1, +4, +2`

Text Solution

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The correct Answer is:
To determine the oxidation states of potassium (K) in the compounds K2O, K2O2, and KO2, we will analyze each compound step by step. ### Step 1: Determine the oxidation state of K in K2O 1. **Identify the oxidation state of oxygen (O)**: In K2O, oxygen has an oxidation state of -2. 2. **Set up the equation**: The compound is neutral, so the sum of the oxidation states must equal 0. - Let the oxidation state of K be x. - The equation is: 2x + (-2) = 0. 3. **Solve for x**: - 2x - 2 = 0 - 2x = 2 - x = +1. **Oxidation state of K in K2O is +1.** ### Step 2: Determine the oxidation state of K in K2O2 1. **Identify the oxidation state of oxygen (O)**: In K2O2 (a peroxide), each oxygen has an oxidation state of -1. 2. **Set up the equation**: The compound is neutral, so the sum of the oxidation states must equal 0. - Let the oxidation state of K be x. - The equation is: 2x + 2(-1) = 0. 3. **Solve for x**: - 2x - 2 = 0 - 2x = 2 - x = +1. **Oxidation state of K in K2O2 is +1.** ### Step 3: Determine the oxidation state of K in KO2 1. **Identify the oxidation state of oxygen (O)**: In KO2 (a superoxide), each oxygen has an oxidation state of -1/2. 2. **Set up the equation**: The compound is neutral, so the sum of the oxidation states must equal 0. - Let the oxidation state of K be x. - The equation is: x + 2(-1/2) = 0. 3. **Solve for x**: - x - 1 = 0 - x = +1. **Oxidation state of K in KO2 is +1.** ### Summary of Results - Oxidation state of K in K2O: +1 - Oxidation state of K in K2O2: +1 - Oxidation state of K in KO2: +1 ### Final Answer The oxidation states of potassium in K2O, K2O2, and KO2 are respectively +1, +1, and +1.
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Knowledge Check

  • Oxidation number of potassium in K_2O, K_2O_2 and KO_2 , respectively:

    A
    `+1, +1, +1 `
    B
    `+1, +4, +1 `
    C
    `+2, +1, + 1 `
    D
    `+1, +1, +2 `
  • Oxidation state of O in KO_(2) is

    A
    `-2`
    B
    0
    C
    `+2`
    D
    None of these
  • Oxidation number of oxygen in K_2O,K_2O_2 and KO_2 respectively is :

    A
    -2,-2,-2
    B
    -2,-1,-2
    C
    `-1,-2,-1/2`
    D
    `-2,-1,-1/2`
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