E(Cu^(2+)//Cu)^(@)=0.34V E(Cu^(+)//Cu)...

`E_(Cu^(2+)//Cu)^(@)=0.34V`
`E_(Cu^(+)//Cu)^(@)=0.522V`
`E_(Cu^(2+)//Cu^(+))^(@)=`

A

` + 0.158 V `

B

` -0.182 `V

C

` -0.158 ` V

D

`0.182 ` V

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Find the equilibrium constant for the reaction Cu^(2+)+In^(2+)hArrCu^(+)+In^(3+) Given that E_("cu^(2+)//Cu^(+))^(@)=0.15V ,? E_(In^(2+)//In^(+))^(@)=-0.4V , E_(In^(3+)//In^(+))^(@)=-0.42V

Find the equilibrium constant that the reaction In^(2+)+Cu^(2+)underset(larr)rarrIn^(3+)+Cu^(+) at 298 K Given E_(Cu^(2+)//Cu^(+))=0.15V, E_(In^(2+)//In^(+))^(@)=-0.40V E_(In^(3+)//In^(+))^(@)=+0.42V

Find the equilibrium constant at 298K for the reaction, Cu^(2+)(aq) +In^(2+)(aq)hArr Cu^(+)(aq) +In^(3+)(aq) Given that E_(Cu^(2+)//Cu^(+))^(@) =0.15V, E_(In^(3+)//In^(-))^(@) =- 0.42V, E_(In^(2+)//In^(+))^(@) =- 0.40V

Calculate equilibrium constant for tha disproportionation reaction : 2Cu^(2+)(aq)rarrCu(s)+Cu^(2+)(aq)" at " 25^(@)C ("Given " E_((Cu^(+)//Cu))^(@)=0.52 V, E_((Cu^(2+)//Cu^(+)))^(@)=0.16 V) .

Calculate emf of the following cell reaction at 2968 K : Ni(s)//Ni^(2+)(0.01 M) || Cu^(2+)(0.1 M)//Cu(s) [Given E_(Ni^(2+)//Ni)^(@)=-0.25" V ",E_(Cu^(2+)//Cu)^(@)=+0.34 " V " ] Write the overall cell reaction.

Find the equilibrium constant for the reaction Cu^(2+)+ 1n^(2+) Cu^(+) + 1n^(3+) Given that E_(CU^(2+)//CU^(+))^(@) = 0.15V, E_(In^(2+)//1n^(+)) = -0.4V E_(1n^(3+)//1n^(+))^(@) = - 0.42V

Given that E_(Cu^(2+)//Cu)^(0)=0.337 and E_(Cu^(+)//Cu^(2+))^(0)=-0.153V . then calculate E_(Cu^(+)//Cu)^(0)

Knowledge Check

Given E_(Ag^(+)//Cu)^(@)=0.80V,E_(Hg^(2+)//Mg)^(@)=0.79V E_(Cu^(2+)//Cu)^(@)=0.34V,E_(Hg^(2+)//Hg)=0.34V Which of the following statement (s) is /are incorrect ?

A

`AgNO_(3)` can be stored in a copper vessel .

B

`Cu(NO_(3))_(2)` can be stored in a magnesium vessel .

C

`Cu(NO_(3))_(2)` can be stored in a silver vessel .

D

`HgCl_(2)` can be stored in a copper vessel .

The equilibrium constant for the reaction, Cu(s)+Cu^(2+) (aq.) hArr 2Cu^(+) (aq.) E_(Cu^(2+)//Cu)^(@)=0.34 V" "E_(Cu^(2+)//Cu)^(@)=0.15 V (Given : log 3.72 = 0.571)

A

`3.72 xx 10^(-6)`

B

`3.72 xx 10^(-5)`

C

`3.72 xx 10^(-7)`

D

`3.72 xx 10^(-8)`

JEE MAINS PREVIOUS YEAR-JEE MAIN-CHEMISTRY

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