In `YDSE`, slab of thickness t and refractive index `mu` is placed in front of any slit. Then displacement of central maximu is terms of fringe width when light of wavelength `lamda` is incident on system is
In `YDSE`, slab of thickness t and refractive index `mu` is placed in front of any slit. Then displacement of central maximu is terms of fringe width when light of wavelength `lamda` is incident on system is
A
`(beta(mu-1)t)/(2lamda)`
B
`(beta(mu-1)t)/(lamda)`
C
`(beta(mu-1)t)/(3lamda)`
D
`(beta(mu-1)t)/(4lamda)`
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The correct Answer is:
B
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In YDSE when slab of thickness t and refractive index mu is placed in front of one slit then central maxima shifts by one fringe width. Find out t in terms of lambda and mu .
In YDSE when slab of thickness t and refractive index mu is placed in front of one slit then central maxima shifts by one fringe width. Find out t in terms of lambda and mu .
A
`(lambda)/((2mu-1))`
B
`(2lambda)/((2mu-1))`
C
`(lambda)/((mu-1))`
D
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A mica slit of thickness t and refractive index mu is introduced in the ray from the first source S_1 . By how much distance of fringes pattern will be displaced?
A mica slit of thickness t and refractive index mu is introduced in the ray from the first source S_1 . By how much distance of fringes pattern will be displaced?
A
`d/D (mu - 1)t`
B
`D/d (mu - 1)t`
C
`(d)/((mu - 1) D)`
D
`D/t (mu - 1)`
In YDSE shown in figure a parallel beam of light is incident on the slits from a medium of refractive index n_(1) . The wavelength of light in this medium is lambda_(1) . A transparent of thickness t and refractive index n_(3) is put in front of one slit. The medium between the screen and the plane of the slits is n_(2) . The phase difference between the light waves reaching point O (symmetrical, relative to the slits) is
In YDSE shown in figure a parallel beam of light is incident on the slits from a medium of refractive index n_(1) . The wavelength of light in this medium is lambda_(1) . A transparent of thickness t and refractive index n_(3) is put in front of one slit. The medium between the screen and the plane of the slits is n_(2) . The phase difference between the light waves reaching point O (symmetrical, relative to the slits) is
A
`(2 pi)/(n_(1) lambda_(1)) (n_(3) - n_(2)) t`
B
`(2 pi)/(lambda_(1)) (n_(3) - n_(2)) t`
C
`(2 pi n_(1))/(n_(2) lambda_(1)) ((n_(3))/(n_(2)) - 1) t`
D
`(2 pi n_(1))/(lambda_(1)) (n_(3) - n_(2))t`
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A plate of thickness t made of material of refractive index mu is placed in front of one of the slits in a double slit experiment . What should be the minimum thickness t which will make the intensity at the centre of the fringe pattern zero ?
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