In `YDSE`, slab of thickness t and refractive index `mu` is placed in front of any slit. Then displacement of central maximu is terms of fringe width when light of wavelength `lamda` is incident on system is
In YDSE when slab of thickness t and refractive index mu is placed in front of one slit then central maxima shifts by one fringe width. Find out t in terms of lambda and mu .
In YDSE shown in figure a parallel beam of light is incident on the slits from a medium of refractive index n_(1) . The wavelength of light in this medium is lambda_(1) . A transparent of thickness t and refractive index n_(3) is put in front of one slit. The medium between the screen and the plane of the slits is n_(2) . The phase difference between the light waves reaching point O (symmetrical, relative to the slits) is
In Young’s double slit experiment a transparent sheet of thickness t and refractive index mu is placed in front of one of the slits and the central fringe moves away from the central line. It was found that when temperature was raised by Deltatheta the central fringe was back on the central line (at C). It is known that temperature coefficient of linear expan- sion of the material of the transparent sheet is alpha . A young scientist modeled that the refractive index of the material changes with temperature as Deltamu"= – gama Deltatheta . Find Deltatheta in terms of other given quantities. D and d are given and have usual meaning.
A plate of thickness t made of a material of refractive index mu is placed in front of one of the slits in a double slit experiment. (a) Find the changes in he optical path due to introduction of the plate. (b) Wht should be the minimum thickness t which will make the intensity at the centre of the fringe pattern zero ? Wavelength of the light used is lamda . Neglect any absorption of light in the plate.
Figure shows a YDSE setup having identical slits S_(1) and S_(2) with d =5 mm and D = 1 m. A monochromatic light of wavelength lamda = 6000 Å is incident on the plane of slit due to which at screen centre O, an intensity I_(0) is produced with fringe pattern on both sides Now a thin transparent film of 11 mu m thickness and refractive index mu = 2.1 is placed in front of slit S_(1) and now interference patten is observed again on screen. After placing the film of slit S_(1) , the intensity at point O screen is :
In Young's double-slit experiment, let A and B be the two slit. A thin film of thickness t and refractive index mu is placed in front of A. Let beta = fringe width. Then the central maxima will shift
In a regular YDSE, when thin film of refractive index mu is placed in front of the upper slit then it is observed that the intensity at the central point becomes half of the original intensity. It is also observed that the initial 3^(rd) maxima is now below the central point and the initial 4^(th) minima is above the central point. Now, a film of refractive index mu_(1) and thickness same as the above film. is put in the front of the lower slit also. It is observed that whole fringe pattern shifts by one fringe width. What is the value of mu_(1) ?
