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Position of an ant ( "S" in metres) movi...

Position of an ant ( "S" in metres) moving in "Y" - "Z" plane is given by `S=2t^(2) hat j+5 hat k` (where "t" is in "],[" second).The magnitude and direction of velocity of the ant at "t=1s" will be:

A

"4m/s" in "y" -direction

B

"4m/s" in "x" -direction "

C

"16m/s" in "y" -direction "

D

"9m/s" in "z" -direction "

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The correct Answer is:
A
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Knowledge Check

  • The position of a particle is given by vec(r) = 3that(i) - 4t^(2)hat(j) + 5hat(k). Then the magnitude of the velocity of the particle at t = 2 s is

    A
    `sqrt(265)m//s`
    B
    `sqrt(276)m//s`
    C
    `sqrt(246)m//s`
    D
    `sqrt(255)m//s`

  • The position of a particle is given by vecr = 2t^(2) hati + 3t hatj + 4hatk where t is in second and the coefficients have proper units for vecr to be in metre. The veca(t) of the particle at t = 1 s is

    A
    `4 m s^(-2)` along y-direction
    B
    `3 m s^(-2)` along x-direction
    C
    `4 m s^(-2)` along x-direction
    D
    `2 m s^(-2)` along z-direction

  • A car moves along a straight line whose equation of motion is given by s=12t+3t^(2)-2t^(3) where s is in metres and t is in seconds. The velocity of the car at start will be :-

    A
    7 m/s
    B
    9 m/s
    C
    12 m/s
    D
    16 m/s
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