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A uniform ladder of mass 10 kg leans aga...

A uniform ladder of mass 10 kg leans against a smooth vertical wall making an angle of `53^0` with it. The other end rests on a rough horizontal floor. Find the normal force and the frictional force that the floor exerts on the ladder

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To solve the problem of finding the normal force and the frictional force that the floor exerts on the ladder, we will follow these steps: ### Step 1: Identify the forces acting on the ladder The forces acting on the ladder include: - The weight of the ladder (W = mg, where m is the mass and g is the acceleration due to gravity). - The normal force (N1) exerted by the floor. - The frictional force (F) exerted by the floor. - The normal force (N2) exerted by the wall. ...
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A stationary uniform rod of mass 'm', length 'l' leans against a smooth vertical wall making an angle theta with horizontal floor. Find the normal force & frictional force that is exerted by the floor on the rod ?

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Knowledge Check

  • A ladder of mass 10kg is held at reat against a smooth wall on a rough ground as shown in figure. The normal reaction between the wall and the ladder is

    A
    50N
    B
    `50sqrt(3)N`
    C
    `(60)/sqrt(3)N`
    D
    100N

  • A ladder 20 ft long is resting angainst a smooth vertical wall at angle of 30^(@) with it Its foot lies on a rough ground with coefficient of friction 0*3 If the weight of the ladder is 30 kg, then a man of 60 kg weight can climb on the ladder up to the height

    A
    `(9sqrt(3)-5)` ft
    B
    `(9sqrt(3)+sqrt(5))ft`
    C
    `9sqrt(3)` ft
    D
    None of these

  • In the figure, a ladder of mass m is shown leaning against a wall. It is in static equilibrium making an angle theta with the horizontal floor. The coefficient of friction between the wall and the ladder is mu_1 and that between the floor and the ladder is mu_2. the normal reaction of the wall on the ladder is N_1 and that of the floor is N_2. if the ladder is about to slip. than

    A
    `mu_1 = 0, mu_2 != and N_2 tan theta = (mg)/(2)`
    B
    `mu_1 != 0, mu_2 =0 and N_1 tan theta = (mg)/(2)`
    C
    `mu_1 != 0, mu_2 !=0 and N_2 = (mg)/(1+mu_1 mu_2)`
    D
    `mu_1 = 0, mu_2 != 0 and N_1 tan theta = (mg)/(2)`

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