A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field, What distance he has to walk to reach the field? b.What is his displacement from his house to the field?

Answer

A, B, C, D

Explanation

a. Distance travelled = 50+40+20
=110 m
b. `AF=AB-BF
=AB-DC
=50-20=30m
` His displacement
`AD=sqrt(AF^2+DF^2)
sqrt(30^2+40^2)
=sqrt(2500)=50m

in /_\ED
tantheta = (DE)/(AE)=30-40=3/4
rarr theta = tan^-(-1)(3/4)` His displacement from his house to the field is 50 m
tan^-1` (3/4)` north to east.