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A simple pendulum of length l ils pulled...

A simple pendulum of length l ils pulled aside to make an angle `theta` with the vertical. Find the magnitude of the torque of the weitht w of the bob about the point of suspension. When is the torque zero?

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To find the magnitude of the torque of the weight \( W \) of the bob about the point of suspension when the pendulum is pulled aside to make an angle \( \theta \) with the vertical, we can follow these steps: ### Step 1: Understand the Setup We have a simple pendulum consisting of a bob of mass \( m \) attached to a string of length \( L \). The bob is displaced to an angle \( \theta \) from the vertical. **Hint:** Visualize the pendulum and identify the forces acting on the bob. ### Step 2: Identify the Forces The only force acting on the bob is its weight \( W \), which acts vertically downward. The weight can be expressed as: \[ W = mg \] where \( g \) is the acceleration due to gravity. **Hint:** Remember that the weight acts downward regardless of the pendulum's position. ### Step 3: Determine the Torque Torque (\( \tau \)) about the point of suspension is given by the formula: \[ \tau = r \times F \] where \( r \) is the distance from the pivot point to the point of application of the force, and \( F \) is the force. In this case, the torque due to the weight of the bob is: \[ \tau = W \cdot D \] where \( D \) is the perpendicular distance from the line of action of the weight to the pivot point. **Hint:** The torque is maximized when the force is applied at the maximum distance from the pivot. ### Step 4: Calculate the Perpendicular Distance \( D \) The perpendicular distance \( D \) can be found using trigonometry. When the bob is at an angle \( \theta \), the perpendicular distance from the weight to the pivot is: \[ D = L \sin \theta \] **Hint:** Use the sine function to relate the angle to the opposite side of the triangle formed by the pendulum. ### Step 5: Substitute \( D \) into the Torque Formula Now substituting \( D \) into the torque equation, we get: \[ \tau = W \cdot (L \sin \theta) \] Thus, the magnitude of the torque is: \[ \tau = W L \sin \theta \] **Hint:** This equation shows how torque depends on both the weight of the bob and the angle \( \theta \). ### Step 6: Determine When the Torque is Zero The torque will be zero when: \[ \sin \theta = 0 \] This occurs when \( \theta = 0 \) (i.e., when the pendulum is in the vertical position). **Hint:** Think about the physical meaning: when the pendulum is vertical, the weight acts directly downward through the pivot, resulting in no torque. ### Final Answer The magnitude of the torque of the weight \( W \) of the bob about the point of suspension is: \[ \tau = W L \sin \theta \] The torque is zero when the pendulum is in the vertical position, i.e., \( \theta = 0 \).

To find the magnitude of the torque of the weight \( W \) of the bob about the point of suspension when the pendulum is pulled aside to make an angle \( \theta \) with the vertical, we can follow these steps: ### Step 1: Understand the Setup We have a simple pendulum consisting of a bob of mass \( m \) attached to a string of length \( L \). The bob is displaced to an angle \( \theta \) from the vertical. **Hint:** Visualize the pendulum and identify the forces acting on the bob. ### Step 2: Identify the Forces ...
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