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Find the angles of /\ABC whose vertices ...

Find the angles of `/_\ABC` whose vertices are `A(-1,3,2), B(2,3,5) and C(3,5,-2)`.

A

`45^@`

B

`60^@`

C

`90^@`

D

`30^@`

Text Solution

Verified by Experts

The correct Answer is:
C

Now DR's of AB = (2+1,3-3,5-2) = (3,0,3) and AC = (3+1,5-3,-2-2) = (4,2,-4)
`thereforecosA=(3xx4+0xx2+3xx-4)/(sqrt(3^2+0+3^2)sqrt(4^2+2^2+(-4)^2))=(12-12)/(sqrt(36)sqrt(36))=0`
`rArr" "angleA=90^@`
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