Home
Class 12
PHYSICS
The period of simple pendulum...

The period of simple pendulum

Text Solution

Verified by Experts

The period of a simple pendulum at a given place is given by
`T=2pisqrt((L)/(g))`
where L is the length of the simple pendulum and g is the acceleration due to gravity at that place. From the above expression, the laws of simple pendulum are as follows :
(1) Law of length : The period of a simple pendulum at a given place (g constant) is directly proportional to the aquare root of its length.
(2) Law of acceleration due to gravity : The period of a simple pendulum of a given length (L constant) is inversely proportional to the aquare root of the acceleration due to gravity.
(3) Law of mass : The period of a simple pendulum does not depend on the mass or material of the bob of the pendulum.
(4) Law of isochronous oscillations or law of isochronism : The period of a simple pendulum does not depend on the amplitude of oscillations, if the amplitude is small.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LAWS AND THEORIES

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Elasticity|1 Videos
  • LAWS AND THEORIES

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Surface tension|1 Videos
  • LAWS AND THEORIES

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Rotation Motion|1 Videos
  • INSTRUMENTS : CONSTRUCTION AND WORKING

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Semiconductors|6 Videos
  • MODEL QUESTION PAPER

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise SECTION- D|5 Videos

Similar Questions

Explore conceptually related problems

The time period of simple pendulum inside a stationary lift is T. If lift starts accelerating upwards with the acceleration of g/2, then the new time period of the simple pendulum will be

What is the time period of a simple pendulum ?

Knowledge Check

  • Time period of simple pendulum of length l at a place, where acceleration due to gravity is g and period T. Then period of simple pendulum of the same length at a place where the acceleration due to gravity 1.02 g will be

    A
    T
    B
    1.02 T
    C
    0.99 T
    D
    1.01 T
  • Time period of simple pendulum is

    A
    `T = 2pi sqrt(l/g)`
    B
    `T = 2pi sqrt(g/l)`
    C
    `T = sqrt(2 pi (l)/(g))`
    D
    `T = (1)/(2pi) sqrt(g/l)`
  • Time period of simple pendulum increase with

    A
    increase in value of g
    B
    increase in amplitude
    C
    decrease in value of g
    D
    decrease in amplitude
  • Similar Questions

    Explore conceptually related problems

    Time period of simple pendulum of wire is independent

    The time period of a simple pendulum in a satellite is

    In order to double the period of a simple pendulum :

    The period of a simple pendulum is doubled, when

    Time period of simple pendulum suspended from a metallic wire