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CONSERVATION OF ANGULAR MOMENTUM

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Law (or principle) of conservation of angular momentum : The angular momentum of a body is conserved if the resultant external torque acting on the body is zero.
Proof : Consider a particle of mass m in motion. Let its position vector with respect to the origin at any instant be `vecr`.
Then, at this instant the linear velocity of this particle is `vecv=(vecdr)/(dt)`, its linear momentum is `vecp=mvecv` and its angular momentum about an axis through the origin is `vecl=vecrxxvecp`.
Consider a case where its angular momentum `vecl` changes with time due to a torque `vecoita` exerted on the particle.
The time rate of change of angular momentum,
`(dvecl)/(dt)=(d)/(dt)(vecrxxvecp)`
`=(dvecr)/(dt)xxvecp+vecr(dvecp)/(dt)`
`=vecvxxmvecv+vecrxxvecF," "` where `(dvecp)/(dt)=vecF`, the force on the particle
`=vecrxxvecF " " (:' vecvxxvecu=0)`
`=vecoita`
Hence, if `vecoita=0,(dvecl)/(dt)=0`
`:. vecl`= constant, i.e., `vecl` is conserved. This proves the law (or principle) of conservation of angular momentum as the result obtained here holds true for every particle belonging to a rotating body.
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Knowledge Check

  • In each of the following questions a statement of Assertion is given followed by a corresponding statements, of Reason just below it of the statements, mark the correct answer as. Assertion (A) Law of areas can be understood as a consequence of conservation of angular momentum. Reason (R) Conservation of angular momentum is valid for any central force and gravitation is a central force.

    A
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    B
    Both Assertion and Reason are correct but Reason Is not the correct explanation of Assertion
    C
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