Find the increase in pressure required to decrease the volume of given mercury by 0.001 %
[ Bulk modulus of mercury = ` 2.8 xx 10^(10) N//m^(2)]`

Explanation

Data : ` (deltaV)/(V) = (0.001)/100 = -10^(-5) , K = 2.8 xx 10^(10)N//m^(2)`
` K = (Deltap)/(DeltaV//V) " " therefore Deltap = -K (DeltaV)/V`
`Delta p = -2.8 xx 10^(10) xx(-10^(-5)) = 2.8 xx 10^(5) N//m^(2)`
This gives the required increase in pressure.