Two material having the dielectric constans `K_(1)` and `K_(2)` are filled between two parallel plates of a capacitor.
where area of each plate is `A` and the distance between the plates is `d`.
The capacitor of the capacitor is:

As the distance between the plates of a parallel plate capacitor decreased

Two dielctric slabs of constant K_(1) and K_(2) have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor ?

How will the voltage (V) between the two plates of a parallel plate capacitor depend on the distance (d) between the plates, if the charge on the capacitor remains the same?

Two dielectric slabs of constant K1 and K2 have been filled in between the plates of a capacitor as shown below. What will be the capacitance of the capacitor

In a parallel plate capacitor of capacitor 1muF two plates are given charges 2muC and 4muC the potential difference between the plates of the capacitor is

A parallel plate capacitor has a capacity c. If a medium of dielectric constant K is introduced between plates, the capacity of capacitor becomes

A parallel plate capacitor having plate area A and separation between the plates d is charged to potential V .The energy stored in capacitor is ....???

Two thin dielectric slabs of dielectric constants K_(1) and K_(2) (K_(1) lt K_(2)) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field E between the plates with distance d as measured from plate P is correctly shown by

A parallel plate capacitor with air between plates (dielectric constant K =2) has a capacitance C. If the air is removed, then capacitance of the capacitor is