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The dimension of ((1)/(2))epsilon(0)E^(2...

The dimension of `((1)/(2))epsilon_(0)E^(2)` (`epsilon_(0)` : permittivity of free space, E electric field

A

(a) `MLT^(-1)`

B

(b) `ML^(2)T^(2)`

C

( c ) `ML^(-1)T^(-2)`

D

( d ) `ML^(2)T^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimension of \(\frac{1}{2} \epsilon_0 E^2\), where \(\epsilon_0\) is the permittivity of free space and \(E\) is the electric field, we can follow these steps: ### Step 1: Understand the formula for energy density The expression \(\frac{1}{2} \epsilon_0 E^2\) represents the energy density (energy per unit volume) stored in an electric field. ### Step 2: Identify the dimensions of energy Energy can be defined as work done. The work done \(W\) is given by the formula: \[ W = F \cdot d \] where \(F\) is force and \(d\) is displacement. The dimension of force \(F\) is: \[ [F] = M L T^{-2} \] Thus, the dimension of work (or energy) becomes: \[ [W] = [F] \cdot [d] = (M L T^{-2}) \cdot (L) = M L^2 T^{-2} \] ### Step 3: Identify the dimensions of volume Volume \(V\) is given by: \[ [V] = L^3 \] ### Step 4: Calculate the dimensions of energy density Energy density is energy per unit volume: \[ \text{Energy Density} = \frac{\text{Energy}}{\text{Volume}} = \frac{M L^2 T^{-2}}{L^3} = M L^{-1} T^{-2} \] ### Step 5: Relate energy density to \(\epsilon_0 E^2\) From the definition of energy density in an electric field: \[ \frac{1}{2} \epsilon_0 E^2 \] we can conclude that the dimensions of \(\epsilon_0 E^2\) must also equal the dimensions of energy density, which we calculated as \(M L^{-1} T^{-2}\). ### Step 6: Conclusion Thus, the dimension of \(\frac{1}{2} \epsilon_0 E^2\) is: \[ [M L^{-1} T^{-2}] \] ### Final Answer The dimension of \(\frac{1}{2} \epsilon_0 E^2\) is \(M L^{-1} T^{-2}\). ---

To find the dimension of \(\frac{1}{2} \epsilon_0 E^2\), where \(\epsilon_0\) is the permittivity of free space and \(E\) is the electric field, we can follow these steps: ### Step 1: Understand the formula for energy density The expression \(\frac{1}{2} \epsilon_0 E^2\) represents the energy density (energy per unit volume) stored in an electric field. ### Step 2: Identify the dimensions of energy Energy can be defined as work done. The work done \(W\) is given by the formula: \[ ...
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Knowledge Check

  • The dimensions of 1/2 epsilon_(0)E^(2) (epsilon_(0)= permittivity of free space, E= electric field) is

    A
    `[MLT^(-1)]`
    B
    `[ML^(-1)T^(-2)]`
    C
    `[MLT^(-2)]`
    D
    `[ML^(2)T^(-1)]`
  • The dimensions of (1)/(2) in_(0) E^(2) , where in_0 is permittivity of free space and E is electric field, is :-

    A
    `[MLT^(-1)]`
    B
    `[ML^(2)T^(-2)]`
    C
    `[ML^(-1)T^(-2)] `
    D
    `[ML^(2)T^(-1)]`
  • Find the dimension of epsilon_(0)E^(2) , where epsilon_(0) is permittivity of free space and E is the electricity field

    A
    `[M^(1) L^(1) T^(-2) A^(1)]`
    B
    `[M^(1) L^(0)T^(-1)]`
    C
    `[M^(1) L^(-1) T^(-2) A^(1)]`
    D
    `[M^(1) L^(-1) T^(-2)]`
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