An object of mass `0.2 kg` executes simple harmonic oscillation along the `x - axis`with a frequency of `(25//pi) Hz`. At the position `x = 0.04`, the object has Kinetic energy of `0.5 J` and potential energy `0.4 J. The amplitude of oscillations is……m.

Explanation

To find the amplitude of the oscillations for the given object in simple harmonic motion (SHM), we can follow these steps:

### Step 1: Understand the total energy in SHM
The total mechanical energy (E) in simple harmonic motion is given by the sum of kinetic energy (KE) and potential energy (PE):
\[ E = KE + PE \]

### Step 2: Substitute the given values
From the problem, we know:
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