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An object of mass 0.2 kg executes simple...

An object of mass `0.2 kg` executes simple harmonic oscillation along the `x - axis`with a frequency of `(25//pi) Hz`. At the position `x = 0.04`, the object has Kinetic energy of `0.5 J` and potential energy `0.4 J. The amplitude of oscillations is……m.

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To find the amplitude of the oscillations for the given object in simple harmonic motion (SHM), we can follow these steps: ### Step 1: Understand the total energy in SHM The total mechanical energy (E) in simple harmonic motion is given by the sum of kinetic energy (KE) and potential energy (PE): \[ E = KE + PE \] ### Step 2: Substitute the given values From the problem, we know: ...
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Knowledge Check

  • An object of mass 1 kg executes simple harmonic oscillations along the x - axis with a frequency of (2)/(pi)Hz. At the position x = 1 m, the object has a kinetic energy of 24 J and potential energy is 8J. The amplitude of the oscillation is

    A
    `(3)/(2)m`
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    8m

  • An object of mass 1kg executes simple harmonic oscillations along the x-axis, with a frequency of (2)/(pi)Hz . At the position x = 1 m, the object has a kinetic energy of 24 J. The amplitude of the oscillation is

    A
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