A screw gauge gives the following reading when used to mesure the diametre of a wire.
Main scale reading : `0mm`
Circular scale reading : `52 divisions`
Given that `1mm` on main scale corresponds to `100` divisions of the circular scale. the diameter of wire from the above data is :

Options

A. (a) `0.052 cm`
B. (b) `0.026 cm`
C. ( c ) `0.005 cm`
D. (d) `0.52 cm`

Answer

A

Explanation

(a) `L.C. = (1)/(100)mm`
Dimeter of wire = MSR + CSR xx L.C. = 0 + (1)/(100) xx 52`
`= 0.52mm = 0.052cm`