The displacement `x` of particle moving in one dimension, under the action of a constant force is related to the time `t` by the equation ` t = sqrt(x) +3`
where `x` is in meters and `t` in seconds . Find
(i) The displacement of the particle when its velocity is zero , and
(ii) The work done by the force in the first ` 6 seconds`.

Explanation

To solve the problem step by step, we will break it down into two parts as per the question.

### Part (i): Finding the displacement of the particle when its velocity is zero.

1. **Given Equation**:
The relationship between displacement \( x \) and time \( t \) is given by:
\[
t = \sqrt{x} + 3
...