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For synthesis of 1-butene, CH(3)MgI shou...

For synthesis of 1-butene, `CH_(3)MgI` should be treated with

A

propene

B

2-chloropropene

C

allyl chloride

D

ethyl chloride

Text Solution

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The correct Answer is:
To synthesize 1-butene using the Grignard reagent `CH3MgI`, we need to follow these steps: ### Step 1: Understand the Grignard Reagent The Grignard reagent `CH3MgI` consists of a methyl group (`CH3`) bonded to magnesium iodide. This reagent acts as a nucleophile, meaning it can donate a pair of electrons to form a bond with an electrophile. **Hint:** Grignard reagents are strong nucleophiles and can react with electrophiles that have a good leaving group. ### Step 2: Identify the Target Compound We want to synthesize 1-butene, which has the structure `CH2=CH-CH2-CH3`. This means we need to create a carbon chain of four carbons, with a double bond between the first and second carbon. **Hint:** The structure of the target compound will guide you in determining what electrophile to use. ### Step 3: Choose the Appropriate Electrophile To form 1-butene, we need a compound that, when reacted with `CH3MgI`, will allow the methyl group to attach and form the desired carbon chain. The options given are: 1. Propene 2. 2-Chloropropene 3. Allyl chloride 4. Ethyl chloride Among these, allyl chloride (`CH2=CH-CH2Cl`) is a suitable choice because it has a leaving group (Cl) that can be displaced by the methyl group from the Grignard reagent. **Hint:** Look for an electrophile that has a good leaving group and can accommodate the addition of the nucleophile. ### Step 4: Reaction Mechanism When `CH3MgI` reacts with allyl chloride, the nucleophilic methyl group (`CH3-`) attacks the carbon atom bonded to the chlorine atom. This results in the displacement of the chlorine atom, forming 1-butene. **Hint:** The mechanism involves nucleophilic attack and leaving group departure, which is typical in reactions involving Grignard reagents. ### Step 5: Conclusion Thus, the correct electrophile to treat with `CH3MgI` for the synthesis of 1-butene is allyl chloride. **Final Answer:** Allyl chloride (Option C).
To synthesize 1-butene using the Grignard reagent `CH3MgI`, we need to follow these steps: ### Step 1: Understand the Grignard Reagent The Grignard reagent `CH3MgI` consists of a methyl group (`CH3`) bonded to magnesium iodide. This reagent acts as a nucleophile, meaning it can donate a pair of electrons to form a bond with an electrophile. **Hint:** Grignard reagents are strong nucleophiles and can react with electrophiles that have a good leaving group. ### Step 2: Identify the Target Compound ...
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Knowledge Check

  • Acetyl bromide reacts with excess of CH_(3)MgI followed by treatment with a saturated solution of NH_(4)Cl gives :

    A
    acetyl iodide
    B
    acetamide
    C
    `2` - methyl - `2` - propanol
    D
    acetone

  • Acetyl bromide reacts with excess of CH_(3)MGI followed by treatement with a saturated solution of NH_(4)C1 gives:

    A
    Acteyl iodide
    B
    Acetamide
    C
    `2-`Methy`1-2`-propanol
    D
    Acetone

  • Ethyl acetate (CH_(3)COOC_(2)H_(5)) is allowed to react with excess of CH_(3)MgI in dry ether and subsequently heated with water. The final product formed is

    A
    `CH_(3)COC_(2)H_(5)`
    B
    `CH_(3)COCH_(3)`
    C
    `(CH_(3))_(3)C-OH`
    D
    `C_(2)H_(5)-underset(OH)underset(|)(C)(CH_(3))_(2)`