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1 g of impure Na(2)CO(3) is dissolved in...

` 1 g` of impure `Na_(2)CO_(3)` is dissolved in water and the solution is made upto `250 mL`. To `50 mL` of this solution, `50 mL` of `0.1 N HCl` is added and the mixture after shaking well required `10 mL` of `0.16 N NaOH` solution for complete neutralization. Calculation percent purity of the sample of `Na_(2) CO_(3)`.

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To find the percent purity of the impure Na₂CO₃ sample, we can follow these steps: ### Step 1: Calculate the milliequivalents of HCl added We know that: - Volume of HCl = 50 mL - Normality of HCl = 0.1 N Milliequivalents of HCl = Volume (mL) × Normality (N) ...
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1 g of impure Na_(2)CO_(3) is dissolved in water and the solution is made upto 250 ml. To 50 ml of this made up solution , 50 ml of 0.1 N HCl is added and the mixture after shaking well required 10 ml of 0.16 N NaOH solution for complete neutrallzation. Calculate \% purity of the sample of Na_(2)CO_(3) .

3.0 g of impure Na_2CO_3 is dissolved in water and the solution is made up to 250 mL . To 50 " mL of " this solution, 50 " mL of " 0.1 N HCL is added and the mixture, after shaking well, required 10 " mL of " 0.16 N NaOH solution for cojmplete neutralisation. Calculate the percentage purity of the sample of Na_2CO_3 .

Knowledge Check

  • 0.7 g "of" Na_(2)CO_(3).xH_(2)O were dissolved in water and the volume was made to 100 mL, 20 mL of this solution required 19.8 mL "of" N//10 HCl for complete neutralization. The value of x is:

    A
    `7`
    B
    `3`
    C
    `2`
    D
    `5`

  • 0.7 g of Na_(2)CO_(3).xH_(2)O was dissolved in water to make 100 mL solution, 20 mL of this solution required 19.8 mL of 0.1 N HCl for complete neutralisation. The value of x is :

    A
    5
    B
    2
    C
    3
    D
    4

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