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In the figure shown, all surfaces are sm...

In the figure shown, all surfaces are smooth and force constant of spring is `10N//m`. Block of mass (2 kg) is attaced with the spring. The spring is compressed by (2m) and then released. Find the maximum distance `d` travelled by the block over the inclined plane. Take `g=10m//s^(2)`.
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Text Solution

Verified by Experts

The correct Answer is:
B

In the final position, block will stop for a moment and then it will return back.
In the initial position system has only spring potential energy `1/2kx^(2)` and in the final position it has only gravitation potential energy.

Since, all surfaces are smooth, therefore mechanical energy will remain conserved.
`rArr E_(i) =E^(f)` or `1/2kx^(2)=mgh=mg(d/2)`
where `h=d sin 30^@=d/2`
`rArr d =kx^2/mg`
Substituting the values we have,
`d=((10)(2)^(2))/((2)(10)`
`=2m`
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Knowledge Check

  • An inclined plane is moving with Constant velocity v = 4 m//s on a horizoontal surface as shown in figure. If a block of mass 2 kg is kept at top of the incline and their is no friction between the block and the incline, then the distance travelled by the incline till the block reaches bottom of the inclined is (g = 10 m//s^(2))

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