A projectile of mass `m` is fired with a velocity `v` from point P at an angle `45^@`. Neglecting air resistance, the magnitude of the change in momentum leaving the point P and arriving at Q is

Options

A. (a) `sqrt2mv`
B. (b) `2mv`
C. (c) `(mv)/(2)`
D. (d) `(mv)/(sqrt2)`

Answer

A

Explanation

`|Deltap|=|Impu lse|=|F*Deltat|`
Here `Deltat=T=(2vsin45^@)/(g)=(sqrt2v)/(g)`
and `|F|=mg`
`:. |Deltap|=(mg)((sqrt2v)/(g))`
`=sqrt2mv`