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A vessel contains a mixture of 7 g of ni...

A vessel contains a mixture of `7 g` of nitrogen and `11 g` carbon dioxide at temperature ` T = 290 K`. If pressure of the mixure is `1 atm (= 1.01 xx 10^5 N//m^2)`, calculate its dencity `(R = 8.31 J//mol - K)`.

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To calculate the density of a mixture of nitrogen and carbon dioxide, we can follow these steps: ### Step 1: Calculate the number of moles of nitrogen and carbon dioxide. 1. **For nitrogen (N₂)**: - Given mass = 7 g - Molar mass of nitrogen (N₂) = 28 g/mol - Number of moles (n₁) = mass / molar mass = 7 g / 28 g/mol = 0.25 mol 2. **For carbon dioxide (CO₂)**: - Given mass = 11 g - Molar mass of carbon dioxide (CO₂) = 44 g/mol - Number of moles (n₂) = mass / molar mass = 11 g / 44 g/mol = 0.25 mol ### Step 2: Calculate the total number of moles in the mixture. - Total number of moles (N_total) = n₁ + n₂ = 0.25 mol + 0.25 mol = 0.5 mol ### Step 3: Calculate the average molar mass of the mixture. - Molar mass of the mixture (M) can be calculated using the formula: \[ M = \frac{(n₁ \cdot M₁) + (n₂ \cdot M₂)}{N_{total}} \] where: - M₁ = Molar mass of nitrogen = 28 g/mol - M₂ = Molar mass of carbon dioxide = 44 g/mol - Plugging in the values: \[ M = \frac{(0.25 \cdot 28) + (0.25 \cdot 44)}{0.5} \] \[ M = \frac{(7 + 11)}{0.5} = \frac{18}{0.5} = 36 \text{ g/mol} \] ### Step 4: Use the ideal gas equation to find the density. The ideal gas equation can be rearranged to find density (ρ): \[ P = \rho \cdot R \cdot T / M \] Rearranging gives: \[ \rho = \frac{P \cdot M}{R \cdot T} \] ### Step 5: Substitute the values into the density formula. - Given: - Pressure (P) = 1.01 x 10^5 N/m² - Molar mass (M) = 36 g/mol = 0.036 kg/mol (convert to kg) - R = 8.31 J/(mol·K) - Temperature (T) = 290 K Substituting these values into the density equation: \[ \rho = \frac{(1.01 \times 10^5) \cdot 0.036}{8.31 \cdot 290} \] ### Step 6: Calculate the density. Calculating the numerator: \[ 1.01 \times 10^5 \cdot 0.036 = 3636 \] Calculating the denominator: \[ 8.31 \cdot 290 = 2410.9 \] Now, calculating density: \[ \rho = \frac{3636}{2410.9} \approx 1.51 \text{ kg/m}^3 \] ### Final Answer: The density of the mixture of nitrogen and carbon dioxide is approximately **1.51 kg/m³**. ---

To calculate the density of a mixture of nitrogen and carbon dioxide, we can follow these steps: ### Step 1: Calculate the number of moles of nitrogen and carbon dioxide. 1. **For nitrogen (N₂)**: - Given mass = 7 g - Molar mass of nitrogen (N₂) = 28 g/mol - Number of moles (n₁) = mass / molar mass = 7 g / 28 g/mol = 0.25 mol ...
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Knowledge Check

  • A vessel contains a mixture of 7 g of nitrogen and 11 g of carbon dioxide at temperature T = 300 K . If the pressure of the mixutre is 1 atm (1 xx 10^(5) N//m^(2)) , its density is (gas constant R = 25//3 J//mol K)

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