Home
Class 11
PHYSICS
Take the values of (prop) from table 20....

Take the values of (prop) from table `20.2`.
A pendulum clock of time period `2 s` gives the correct time at `30^@ C`. The pendulum is made of iron. How many seconds will it lose or gain per day when the temperature falls tp `0^@ C`? `alpha _(Fe) = 1.2 xx 10^-5 (.^@ C)^-1`.

Text Solution

Verified by Experts

The correct Answer is:
A

`Delta T = 1/2 T (alpha Delta theta) `
Temperature is decreased. Hence, (l) or (T) will decrease. So, it will gain time.
Time gained = `(Delta T)/(T')t ~~ (Delta T)/T t` `(as T' ~~ T)`
= `1/2 alpha Delta theta t = 1/2(1.2 xx 10^-5)(30)(24 xx 60 xx 60)`
= `15.55 s`.
Promotional Banner

Topper's Solved these Questions

  • THERMOMETRY,THERMAL EXPANSION & KINETIC THEORY OF GASES

    DC PANDEY|Exercise Exercise 20.3|7 Videos
  • THERMOMETRY,THERMAL EXPANSION & KINETIC THEORY OF GASES

    DC PANDEY|Exercise Exercise 20.4|3 Videos
  • THERMOMETRY,THERMAL EXPANSION & KINETIC THEORY OF GASES

    DC PANDEY|Exercise Exercise 20.1|5 Videos
  • THERMOMETRY THERMAL EXPANSION AND KINETIC THEORY OF GASES

    DC PANDEY|Exercise Medical entrance gallary|30 Videos
  • UNIT AND DIMENSIONS

    DC PANDEY|Exercise Assertion And Reason|2 Videos

Similar Questions

Explore conceptually related problems

A clock which keeps correct time at 20^@C has a pendulum rod made of brass . How many seconds will it gain or lose per day when temperature falls to 0^@C ? [alpha=18xx10^(-6)//^@C]

A clock having a brass pendulum beats seconds at 30^@C . How many seconds will it lose or gain per day when temperature falls to 10^@C ? Given alpha for brass =(1.9xx10^-5)^@C^-1 .

A second's pendulum gives correct time at 25^(@)C . The pendulum shaft is thin and is made of steel. How many second will it lose per day at g 35^(@)C ? (alpha_(steel)=11xx10^(-5)//^(@)C)

A clock while keeps correct time at 30^(@)C has a pendulum rod made of brass. The number of seconds it gains (or) looses per second when the temperature falls to 10^(@)C is [ alpha of brass = 18 xx 10^(-6//@)C ]

A second's pendulum clock has a steel wire. The clock is calibrated at 20^@ C . How much time does the clock lose or gain in one week when the temperature is increased to 30^@ C ? alpha_(steel = 1.2 xx 10^-5(^@ C)^-1 .

A pendulum clock gives correct time at 20^° C. How many seconds will it lose per day at 40^° C? (alpha = 5 xx 10^-6 /°C)

A pendulum clock keeps correct time at 0^(@)C . Its mean coefficient of linear expansions is alpha//.^(@)C , then the loss in seconds per day by the clock if the temperature rises by t^(@)C is

A pendulum clock shows correct time at 0^(@)C . At a higher temperature the clock.