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Take the values of (prop) from table 20....

Take the values of (prop) from table `20.2`.
A pendulum clock of time period `2 s` gives the correct time at `30^@ C`. The pendulum is made of iron. How many seconds will it lose or gain per day when the temperature falls tp `0^@ C`? `alpha _(Fe) = 1.2 xx 10^-5 (.^@ C)^-1`.

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta T = 1/2 T (alpha Delta theta) `
Temperature is decreased. Hence, (l) or (T) will decrease. So, it will gain time.
Time gained = `(Delta T)/(T')t ~~ (Delta T)/T t` `(as T' ~~ T)`
= `1/2 alpha Delta theta t = 1/2(1.2 xx 10^-5)(30)(24 xx 60 xx 60)`
= `15.55 s`.
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Knowledge Check

  • A clock which keeps correct time at 20^@C has a pendulum rod made of brass . How many seconds will it gain or lose per day when temperature falls to 0^@C ? [alpha=18xx10^(-6)//^@C]

    A
    155.5 s
    B
    15.55 s
    C
    25.55 s
    D
    18.55 s

  • A second's pendulum gives correct time at 25^(@)C . The pendulum shaft is thin and is made of steel. How many second will it lose per day at g 35^(@)C ? (alpha_(steel)=11xx10^(-5)//^(@)C)

    A
    `1.75s`
    B
    `2.5s`
    C
    `3.5s`
    D
    `4.75s`

  • A clock while keeps correct time at 30^(@)C has a pendulum rod made of brass. The number of seconds it gains (or) looses per second when the temperature falls to 10^(@)C is [ alpha of brass = 18 xx 10^(-6//@)C ]

    A
    `18 xx 10^(-6) sec`
    B
    `18 xx 10^(-5) sec`
    C
    `0.0018 sec`
    D
    `0.018 sec`

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