Find the number of degrees of freedom of molecules in a gas. Whose molar heat capacity
(a) at constant pressure `C_p = 29 J mol^-1 K^-1`
(b) `C = 29 J mol^-1 K^-1` in the precess (pT) = constant.

Answer

A, B, C

Explanation

(a) `C_p = (1 + f//2) R`
`29 = (1 +f//2) 8.31`
Solving, we get
`f = 5`
(b) `pT = constant`
`:. p (pV) = constant`
or `pV^(1//2) = constant`
( C ) in the process `(pV^x)` = constant is given by.
`C = C_V + (R)/(1 - x) = f/2 R + (R)/(1 - x)`
`:. 29 = 8.31 (f/2 + 1/(1 - 1//2))`
Solving, we get `f = 3`.