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One mole of a monoatomic ideal gas is ta...

One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure.
`T_A=1000K` and `2p_A=3p_B=6p_C`

`[Ass um e(2/3)^0.4=0.85` and `R=(25)/(3)JK^-1mol^-1]`
The temperature at B is

A

350K

B

1175K

C

850K

D

577K

Text Solution

Verified by Experts

The correct Answer is:
C
In adiabatic process,
`p^(1-gamma)T^gamma=`constant or `Tpropp^((gamma-1)/(gamma))`
`:.` `(T_B)/(T_A)=((p_B)/(p_A))^((gamma-1)/(gamma)`
`:.` `T_B=(1000)(2/3)^((5//3-1)/(5//3))`
`=(1000)(2/3)^0.4=850K`
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