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In Young's double slit experiment, dista...

In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is `5460 Å`. Then, angular position of first dark fringe is approximately

A

`0.08^@`

B

`0.16^@`

C

`0.20^@`

D

`0.32^@`

Text Solution

Verified by Experts

The correct Answer is:
B
`dsin theta = lambda/2`
:. `Theta = sin^-1(lambda/(2d))= sin^-1((5460 xx 10^-10)/(2xx 0.1 xx 10^-3))`
`= 0.16^@` .
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