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A beam of light consisting of two wavele...

A beam of light consisting of two wavelengths 6500Å and 5200Å is used to obtain interference fringes in YDSE. The distance between slits is 2mm and the distance of the screen form slits is 120 cm. What is the least distance from central maximum where the bright due to both wavelengths coincide?

A

0.156cm

B

0.312cm

C

0.078cm

D

0.468cm

Text Solution

Verified by Experts

The correct Answer is:
A

`(n_1lambda_1D)/d = (n_2lambda_2D)/d`
or `n_1/n_2 = lambda_1/lambda_2 = 5200/6500= 4/5 `
` :.` 4th maxima of `lambda_1` coincides with 5th maxima
of `lambda_2`.
` y_min = (4lambda_1 D)/d `
` = (4 xx 6500 xx 10^-10 xx 1.2)/(2 xx (10^(-3)))`
` = 1.56 xx 10^(-3)m = 0.156 cm ` .
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A beam of light consisting of two wavelengths 6500Å and 5200Å is used to obtain interference fringes in a young's double slit experiment the distanece between the slits is 2mm and the distance between the plane of the slits and screen is 120 cm. (a). Find the distance of the third bright fringe on the screen from the central maxima for the wavelength 6500Å (b). What is the least distance from the central maxima where the bright fringes due to both the wave lengths coincide?

A beam of light consisting of two wavelength 6500Å&5200Å is used to obtain interferance fringes in a young's double slit experiment .The distance between the slits is 2.0mm and the distance between the plane of the slits and thescreen is 120cm ,.what is the least distance from the central maximum where the bright fringes due to both the wave length coincides?

Knowledge Check

  • A beam of light contains two wavelengths 6500Å and 5200Å They form interference fringes in Young's double slit experiment. What is the least distance (approx) from central maximum. Where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.

    A
    `0.16 cm`
    B
    `0.32 cm`
    C
    `0.48 cm`
    D
    `1.92 cm`
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