Two coherent monochromatic light beams of amplitude 3 and 5 units are superposed . The maximum and minimum possible intensities in the resulting beams are in the ratio

Answer

B

Explanation

It is given that the amplitudes `A_(1)` and `A_(2)` are in the ratio `(A_(1))/(A_(2))=3/5`
`therefore ` After superposition the maximum and minimum intensities will be in the ratio
`(I_("max"))/(I_("min"))=((A_(1)+A_(2))^(2))/((A_(2)+A_(2))^(2))=((3+5)^(2))/((3-5)^(2))=(8^(2))/((-2)^(2))=(64)/(4)=(16)/(1)`