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In Young's double slit experiment carried out with wavelength `lamda=5000`Å, the distance between the slits is 0.2 mm and the screen is 2 m away from the slits. The central maxima is at n=0. the third maxima will be at a distance x (from central maxima) is equal to

A

5.0 cm

B

0.5 cm

C

4.67 cm

D

1.5 cm

Text Solution

Verified by Experts

The correct Answer is:
D
For third maxima, `x=(3Dlamda)/(d)`
`=(3xx2xx5000xx10^(-10))/(0.2xx10^(-3))`
`=(6xx5xx10^(-7))/(2xx10^(-4))`
`=15mm=1.5`cm
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  • In Young's double slit experiment carried out with light of wavelength lamda= 5000 Å, the distance between the slits is 0.2 mm and screen is 2.0 m away from the slits. The central maximum is at n=0. the third maximum will be formed at a distance x (from the central maxima) equal to

    A
    0.5 cm
    B
    1.67 cm
    C
    1.5 cm
    D
    5 cm

  • The Young's double slit experiment is carried out with light of wavelength 5000Å . The distance between the slits is 0.2 mm and the screen is at 200 cm from the slits. The central maximum is at y=0 . The third maximum will be at y equal to

    A
    `1.67 cm`
    B
    `1.5 cm`
    C
    `0.5 cm`
    D
    `5.0 cm`

  • In Young's double slit experiment, wavelength lambda=5000Å the distance between, the slits is 0.2mm and the screen is at 200cm from the slits. The central maximum is at x=0 The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

    A
    `1.67 cm`
    B
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    C
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    D
    `5.0 cm`

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