In Young's double slit experiment carried out with wavelength `lamda=5000`Å, the distance between the slits is 0.2 mm and the screen is 2 m away from the slits. The central maxima is at n=0. the third maxima will be at a distance x (from central maxima) is equal to

Options

A. 5.0 cm
B. 0.5 cm
C. 4.67 cm
D. 1.5 cm

Answer

D

Explanation

For third maxima, `x=(3Dlamda)/(d)`
`=(3xx2xx5000xx10^(-10))/(0.2xx10^(-3))`
`=(6xx5xx10^(-7))/(2xx10^(-4))`
`=15mm=1.5`cm