A Sphere pure rolls on a rough inclined plane with initial velocity 2.8 m/s. Find the maximum distance on the inclined plane

Answer

A

Explanation

`a=(g sin theta)/( 1+k^(2)//r^(2))`
`I=(2)/(5)mr^(2)=mk^(2)`
`(k^(2))/(r^(2))=(2)/(5)`
`a=(g sin theta)/( 1+2//5)`
`2.8^(2)=2(gxx(1)/(2))/((7)/(2)) xxS`
`S=2.8^(2) xx(7)/(20)`
`S=2.744m`